ELECTRONIC TASK: Series vs Parallel Circuit Analysis By Hidayet Hesenli,Ramal Demirli, Nezrin Serbetli Verified by: Physics Teacher Azerbaijan Telman Askeraliyev (Fizika Muellimi, Azerbaijan, Baku

This project investigates two types of electrical circuits:

Series Circuit

Total resistance:

Rtotal $=100+100=200 \Omega=100+100=200 \Omega \mathrm{R}($ total $)=100+100=200 \Omega$ Current: $\mathrm{I}=\mathrm{V} / \mathrm{R}=9 / 200=0.045 \mathrm{~A}$

Voltage across each bulb:

$\mathrm{V}=\mathrm{I} \times \mathrm{R}=0.045 \times 100=4.5 \mathrm{VV}=\mathrm{I} \times \mathrm{R}=0.045 \times 100=4.5 \mathrm{~V}$

Result: Lower voltage → dim light

Total resistance: $1 / \mathrm{R}=1 / 100+1 / 100 \Rightarrow \mathrm{R}=50 \Omega$

Current: $\mathrm{I}=9 / 50=0.18 \mathrm{~A}$

Voltage across each bulb: $\mathrm{V}=\mathrm{I} \times \mathrm{R}=0.18 \times 50=9 \mathrm{~V}$ Result: Full voltage → bright light

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